Last Living Member Of 1948 Cleveland Indians Team Will Attend Game 6
Eddie Robinson is the last living member of the 1948 World Series champion Cleveland Indians team, and he will be in the stands tonight for Game 6.
Robinson drove in the World Series winning run for Cleveland and defeated the Boston Braves in Game 6 of the 1948 Fall Classic. The Indians have invited Robinson and his wife, Bette, to sit in a suite to watch another Game 6 68 years later, MLB.com’s Jordan Bastian reports.
The Indians lead the series 3-2 going into the game Tuesday night, which they hope will have a similar result to the game Robinson played in back in ’48. (RELATED: Cleveland Fans Had A Tough Decision To Make Last Night)
“That was such an exciting time,” Robinson told the MLB Network of the 1948 run. “All we wanted to do was win the American League pennant. Once we did that, we were a little bit free and easier in the World Series.”
The 95-year-old Cleveland hero reminisced on the wild path the 1948 Indians took to get to and eventually win the World Series in the interview.
“That was a tough year,” Robinson said. “That whole year was a nip-and-tuck year with the Yankees and the Red Sox. Philadelphia was in the mix and Cleveland. All year was tough.”
“All we had to do was beat Detroit on a Sunday and we had it clinched, but Hal Newhouser beat us and we lost the toss,” Robinson told the MLB Network. “After the game, we just got on the train and went to Boston and the next day we got there at 8 o’clock in the morning, checked in the Kenmore hotel and went to the ballpark and won, 8-3,” against the Red Sox to clinch their spot in the World Series.
Over the course of the World Series-winning season, Robinson hit 16 home runs and 83 RBIs in his 134 games as the starting first baseman. He went 2-for-4 in Game 6 of the World Series in which he brought in the final run in the 4-1 victory.
I’m sure Indians fans will be glad to have him back in the park for another potential World Series championship win.