LA Ram Becomes Highest-Paid Defensive Player In NFL History. Here’s How Much He’s Making
Los Angeles Rams defensive end Aaron Donald just made history.
The four-time Pro Bowler just inked the largest contract for a defensive player in NFL history, multiple sources are reporting.
According to ESPN’s Adam Schefter, Donald just signed on for a six-year extension with the Rams worth about $135 million in total — with $87 million guaranteed. (RELATED: HERE’S HOW DANICA PATRICK CELEBRATED AARON RODGERS’ RECORD-SHATTERING NFL DEAL)
Long time coming: Rams and Aaron Donald finalizing a record 6-year, $135 million, including $87 million guaranteed, per source. Richest defensive deal in NFL history.
Donald now tied to LA for next seven years. And he will be ready for Monday night opener vs. Raiders.
— Adam Schefter (@AdamSchefter) August 31, 2018
The Rams confirmed the news minutes later on Twitter.
— Los Angeles Rams (@RamsNFL) August 31, 2018
Donald, an all-American out of Pittsburgh, has been in the NFL for four seasons and was quickly recognized as one of the best defensive players in the league. Last season, he was named Defensive Player Of The Year. (RELATED: NEW YORK GIANTS STAR INKS INSANE CONTRACT EXTENSION. HERE’S HOW MUCH HE’S GETTING PAID)
There must be something in the locker room water across the country this month. Earlier this week, Aaron Rodgers signed a record-breaking deal with the Green Bay Packers, making him the highest paid player in the NFL. Also this week, wide receiver Odell Beckham Jr. inked a $95 million deal with the Giants — putting him handsomely above his counterparts in terms of salary.
As speculation about declining NFL ratings heats up before the start of this season, it will be interesting to see whether teams can continue to justify paying its players so much money.